electric machines by nagrath and kothari pdf download

20 cmĠ.2 0.3 0.5 H(kAT/m) *Cold rolled grain oriented steel P2.3, calculate the exciting current required to establish a flux of 2 mWb in the air-gap. Effect of air-gaps on iron path length is negligible. The corresponding analogous electrical circuit is given in Fig. The corresponding electrical analog of magnetic circuit is shown in Fig. Assume mr for iron of the core to be (a) P2.2, find the flux density and flux in each of the outer limbs and the central limbs. If conductor is normal to the plane of the loop, flux through loop is zero, independent of its relative location. What would be the loop flux if the loop is placed such that the conductor is normal to the plane of the loop? Does the loop flux in this case depend upon the relative location of the loop with respect to the conductor? Solution 2d At distance r from conductor H=įlux passing through elemental strip df = B dA = Determine the expression for the total flux passing through the loop. The centre line of the square is at distance b from the conductor. 2.1 A square loop of side 2 d is placed with two of its sides parallel to an infinitely long conductor carrying current I.

Tata McGraw Hill Education Private Limited NEW DELHI McGraw-Hill Offices New Delhi New York St Louis San Francisco Auckland Bogotá Caracas Kuala Lumpur Lisbon London Madrid Mexico City Milan Montreal San Juan Santiago Singapore Sydney Tokyo TorontoĬHAPTER 2: MAGNETIC CIRCUITS AND INDUCTION Note Unless otherwise specified, leakage and fringing are neglected.

Electric machines by nagrath and kothari pdf download